WebIt is given that LCM (p,q)=r 2t 4s 2. That is, at least one of p and q must have r 2,t 4 and s 2 in their prime factorizations. Now, consider the cases for power of r as follows: Case 1: p … WebIf LCM of p,q is r^2 t^4 s^2 where r,s,t are prime numbers and p,q are positive integers . Then thenumber of ordered pairs (p,q) is

If LCM of p,q is r^2 t^4 s^2 where r,s,t are prime numbers and p,q …

Web7 apr. 2024 · First of all we will see the values given to us. So the values are given as If LCM ( p, q, r) = 420 , HCF ( p, q, r) = 1 , HCF ( p, q) = 3 , HCF ( q, r) = 5 and H C F ( p, r) = 1 So by using the formula, we have p. q. r = [ L C M ( p, q, r) H C F ( p, q) H C F ( q, r) H C F ( p, r) H C F ( p, q, r)] Now on substituting the values, we get WebAnswer (1 of 10): In such type of questions we need to first see that what is common in both the numbers. Here, a^2 b^2 is comman in a^3b^2 and b^3a^2. Thus , proceed for … undifferentiated gonads definition

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Web⇒ LCM of p, q, r = pqr ⇒ Product of LCM and HCF = pqr × 1 = pqr ∴ Reciprocal of product = 1/pqr The correct option is 2 i.e. 1/pqr Co-prime number: Two numbers are co-prime if … Web7 nov. 2024 · If r,s,t are prime numbers and p,q are the positive integers such that LCM of p,q is r^2t^4s^2, then find the number of ordered pair (p,q).#math #mathematics... If r,s,t... WebOutput: Total possible pair with GCD 2 & LCM 12 = 4. Analysis of above algorithm Auxiliary Space: O(1) Time Complexity : O(sqrt(L/G) * log(L/G)). For time complexity to find number of distinct prime factors we need O(sqrt(L/G) * log (L/G)) time, Here sqrt(L) iterations are there in the worst case and in each iteration O(log L/G) iterations again. undifferentiated highland